2x^2-9x-5-3x=9

Solution for 2x^2-9x-5-3x=9 equation:

2x^2-9x-5-3x=9

We move all terms to the left:

2x^2-9x-5-3x-(9)=0

We add all the numbers together, and all the variables

2x^2-12x-14=0

a = 2; b = -12; c = -14;
Δ = b2-4ac
Δ = -122-4·2·(-14)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-16}{2*2}=\frac{-4}{4}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+16}{2*2}=\frac{28}{4}
=7
$